Answer:
Bulb will remain at constant brightness for 6 hour
Explanation:
We have given resistance of the bulb R = 4 ohm
Potential difference of the battery V = 2 volt
So current [tex]i=\frac{V}{R}=\frac{2}{4}=0.5A[/tex]
Capacity of the battery is given as 3 amp hour
We have to find the time by which bulb will remain at constant brightness
So time will be [tex]=\frac{3}{0.5}=6hour[/tex]
So bulb will remain at constant brightness for 6 hour