An oil tanker breaks apart and starts leaking. As time goes on, the rate at which the oil is leaking out will diminish. Suppose that "t" hours after the tanker breaks apart, the oil is leaking out at a rate of R(t)=(0.7)/(1+t^2) million gallons per minute. Then ___ million gallons of oil will leak out in the first 3 hours after the shipwreck.

Respuesta :

The quantity of oil in the first 180 minutes was 62.78 million gallons.

Integration

It is the reverse of differentiation.

Given

An oil tanker breaks apart and starts leaking. As time goes on, the rate at which the oil is leaking out will diminish.

The tanker breaks apart, the oil is leaking out at a rate of R(t).

[tex]\rm R(t) = \dfrac{0.7}{1 + t^2}[/tex], where t is time in minutes.

How much a million gallons of oil will leak out in the first 3 hours after the shipwreck?

Convert the hours into minutes.

1 hours = 60 minutes

3 hours = 180 minutes

Then the quantity of oil in the first 180 minutes will be

V(t) = R(t)

Integrate the function.

[tex]\rm V(t) = \int_0^{180} R(t) dt\\\\V(t) = \int_0^{180} \dfrac{0.7}{1+t^2} dt\\\\V(t) = 0.7 \int_0^{180} \dfrac{1}{1 + t^2}dt\\\\V(t) = 0.7[tan^{-1}t]_0^{180}\\\\V(t) = 0.7 [tan^{-1}180 -tan^{-1}0]\\\\V(t) = 0.7 * 89.682\\\\V(t) = 62.78[/tex]

Thus, the quantity of oil in the first 180 minutes was 62.78 million gallons.

More about the integration link is given below.

https://brainly.com/question/18651211