A woman has money in two accounts. One account pays 5% annual interest, whereas the other pays 10% annual interest. If she has $800 more invested in 10% than she does at 5% and her total interest for a year is $250, how much does she have in each account?

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Answer:

She have $1133.33 in account which pays  5% annual interest and he have $1933.33 in account which pays 10% annual interest

Step-by-step explanation:

Let x be the amount she invested at 5% annual interest

She invested $800 more in 10%

So, she invested x+800 at 10% annual interest

Case 1:

Principal = x

Time = 1 year

Rate of interest = 5%

[tex]Si =\frac{P \times R \times T}{100}[/tex]

[tex]SI=\frac{x \times 5 \times 1}{100}[/tex]

[tex]SI=\frac{5}{100}x[/tex]

Case 2:

Principal = x+800

Time = 1 year

Rate of interest = 10%

[tex]Si =\frac{P \times R \times T}{100}[/tex]

[tex]SI=\frac{(x+800) \times 10 \times 1}{100}[/tex]

[tex]SI=\frac{10}{100}(x+800)[/tex]

Interest = Amount - principal = 880+1.1x-x=880+0.1x

Her total interest for a year is $250

So, [tex]\frac{5}{100}x+\frac{10}{100}(x+800)=250[/tex]

[tex]\frac{5}{100}x+\frac{10}{100}(x+800)=250[/tex]

[tex]\frac{5}{100}x+\frac{10}{100}x+80=250[/tex]

[tex]\frac{15}{100}x+80=250[/tex]

[tex]\frac{15}{100}x=250-80[/tex]

[tex]x=170 \times \frac{100}{15}[/tex]

[tex]x=1133.33[/tex]

So the amount she invested at 5% annual interest is $1133.33

She invested at 10% annual interest=x+800=1133.33+800=1933.33

Hence she have $1133.33 in account which pays  5% annual interest and he have $1933.33 in account which pays 10% annual interest

The amount she has in the account that an annual interest of 5% is $3400.

The amount she has in the account that an annual interest of 10% is  $4,200.

What is the system of linear equations that represent the question?

x - y = $800 equation 1

0.1x + 0.05y = $250 equation 2

Where:

  • x = amout invested in the account that earns a 10% interest
  • y = amout invested in the account that earns a 5% interest

How much was invested in the account that earns a 5% interest?

Multiply equation 1 by 0.1

0.1x - 0.1y = 80 equation 3

Subtract equation 3 from equation 2

0.05y = 170

Divide both sides by 0.05

y = $3,400

How much was invested in the account that earns a 5% interest?

Substitute for y in equation 1

x - 3400 = 800

x = 3400 + 800

x = $4,200

To learn more about simultaneous equations, please check: https://brainly.com/question/25875552