Answer:
Force on the ball will be 4350 N
Explanation:
We have given that mass of the baseball m = 0.145 kg
Initial velocity of the baseball u = 40 m/sec
And final velocity v = - 50 m/sec ( in opposite direction )
So change in momentum = [tex]=0.145\times (40-(-50))=13.05kgm/sec[/tex]
Time is given as [tex]t=3ms=3\times 10^{-3}sec[/tex]
We know that change in momentum is given by impulse
So [tex]F\times t=13.05[/tex]
[tex]F\times 3\times 10^{-3}=13.05[/tex]
[tex]F=4350N[/tex]
