Respuesta :
Answer: The percent yield of silver is 86.96 %
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] Β Β Β .....(1)
Given mass of copper = 40.0 g
Molar mass of copper = 63.55 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of copper}=\frac{40.0g}{63.55g/mol}=0.629mol[/tex]
The given chemical equation follows:
[tex]Cu+2AgNO_3\rightarrow Cu(NO_3)_2+2Ag[/tex]
By Stoichiometry of the reaction:
1 mole of copper produces 2 moles of silver
So, 0.629 moles of copper will produce = [tex]\frac{2}{1}\times 0.629=1.258mol[/tex] of silver
Now, calculating the mass of silver from equation 1, we get:
Molar mass of silver = 107.9 g/mol
Moles of silver = 1.258 moles
Putting values in equation 1, we get:
[tex]1.258mol=\frac{\text{Mass of silver}}{107.9g/mol}\\\\\text{Mass of silver}=(1.285mol\times 107.9g/mol)=135.7g[/tex]
To calculate the percentage yield of silver, we use the equation:
[tex]\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100[/tex]
Experimental yield of silver = 118 g
Theoretical yield of silver = 135.7 g
Putting values in above equation, we get:
[tex]\%\text{ yield of silver}=\frac{118g}{135.7g}\times 100\\\\\% \text{yield of silver}=86.96\%[/tex]
Hence, the percent yield of silver is 86.96 %
