Answer:
a)a= 4.62 m/s²
b)μ = 0.462
Explanation:
Given that
m= 1200 kg
r = 70 m
v= 18 m/s
a)
Centripetal acceleration ,a
[tex]a=\dfrac{v^2}{r}[/tex]
By putting the values
[tex]a=\dfrac{v^2}{r}[/tex]
[tex]a=\dfrac{18^2}{70}\ m/s^2[/tex]
a= 4.62 m/s²
b)
To keep the car from slipping ,the radial force should be equal to the friction force
[tex]Fr=m\dfrac{v^2}{r}[/tex]
[tex]\mu mg=m\dfrac{v^2}{r}[/tex]
[tex]\mu =\dfrac{v^2}{rg}[/tex]
By putting the values
[tex]\mu =\dfrac{v^2}{rg}[/tex]
[tex]\mu =\dfrac{18^2}{70\times 10}[/tex]     ( take g =10 m/s²)
μ = 0.462
