Answer:
The equation of line whose x-intercept is 5 and whose y-intercept is 3
is given as 5 y + 3x = 15.
Step-by-step explanation:
Here, the given x - intercept = 5.
⇒ The point on the given equation is (x,0) = (5,0)
And, the y- intercept is given as 3
⇒ The point on the given equation is (0,y) = (0,3)
So, the two points given on the equation of line is A(5,0) and B(0,3)
Now, the slope of the line equation [tex]m = \frac{y_2 - y_2}{x_2-x_1}[/tex]
So, here the slope of line AB is [tex]m = \frac{3- 0}{0-5} = -\frac{3}{5}[/tex]
Now by POINT SLOPE FORMULA:
The equation of a line with point (x0,y0) and slope m is given as:
(y- y0) = m (x-x0)
⇒The equation of line AB is given as
[tex]( y - 0) = -\frac{3}{5} (x -5)\\\implies 5 y = -3x + 15\\\implies 5 y + 3x = 15[/tex]
Hence, the equation of line AB is given as 5 y + 3x = 15.
