Answer: The final temperature of the sample is 62.66°C
Explanation:
To calculate the amount of heat absorbed, we use the equation:
[tex]Q=mc\Delta T[/tex]
where,
Q = heat absorbed = 16.7 kJ = 16700 J (Conversion factor: 1 kJ = 1000 J)
m = Mass of the sample = 225 g
c = specific heat capacity of sample = [tex]1.74J/g.^oC[/tex]
[tex]\Delta T[/tex] = change in temperature = [tex]T_2-T_1=(T_2-20.0)[/tex]
Putting values in above equation, we get:
[tex]16700=225g\times 1.74J/g.^oC\times (T_2-20)^oC\\\\T_2=62.66^oC[/tex]
Hence, the final temperature of the sample is 62.66°C
