Answer:
[tex] \lambda = 3.21 \ cm[/tex]
Explanation:
given,
width of narrow slit = 4.8 cm
minimum angle of diffraction = θ = 42°
wavelength of the microwave = ?
condition for the diffraction for single slit diffraction
[tex]d sin \theta = m \lambda[/tex]
for the first minima m = 1
[tex]d sin \theta = \lambda[/tex]
wavelength of microwave radiation is equal to
[tex] \lambda = d sin \theta[/tex]
[tex] \lambda = 4.8\times sin 42^0[/tex]
[tex] \lambda = 3.21 \ cm[/tex]
the wavelength of microwaves is equal to [tex] \lambda = 3.21 \ cm[/tex]
