Answer : The specific heat of substance is [tex]0.235J/g^oC[/tex]
Explanation :
Formula used :
[tex]Q=m\times c\times \Delta T[/tex]
or,
[tex]Q=m\times c\times (T_2-T_1)[/tex]
where,
Q = heat needed = 4.90 kJ = 4900 J
m = mass of sample = 894.0 g
c = specific heat of substance = ?
[tex]T_1[/tex] = initial temperature = [tex]-5.8^oC[/tex]
[tex]T_2[/tex] = final temperature = [tex]17.5^oC[/tex]
Now put all the given value in the above formula, we get:
[tex]4900J=894.0g\times c\times [17.5-(-5.8)]^oC[/tex]
[tex]c=0.235J/g^oC[/tex]
Therefore, the specific heat of substance is [tex]0.235J/g^oC[/tex]
