To solve this problem it is necessary to apply the concepts related to simple harmonic movement.
The maximum speed from the simple harmonic motion is given as
[tex]V = A\sqrt{\frac{K}{m}}[/tex]
Where,
K = Spring constant
m = mass
At this case m is a constant then
[tex]V \propto \sqrt{K}[/tex]
then the ratio is given by
[tex]\frac{v_2}{v_1}=\sqrt{\frac{K_1}{K_2}}[/tex]
According the statement,
[tex]v_2 = \sqrt{\frac{K_1}{K_2}}v_1[/tex]
[tex]v_2 = 2v_1[/tex]
Therefore the maximum speed becomes double: 2) It would increase by a factor of 2.