A barge floating in fresh water (rho = 1000 kg/m3) is shaped like a hollow rectangular prism with base area A = 550 m2 and height H = 2.0 m. When empty the bottom of the barge is located H0 = 0.55 m below the surface of the water. When fully loaded with coal the bottom of the barge is located H1 = 1.7 m below the surface.

Question

contestada

Respuesta :

CarliReifsteck CarliReifsteck · Answer 1 · 2019-11-26T08:03:17+01:00

Answer:

The buoyant force is 2964500 N.

Explanation:

Given that,

Density of water = 1000 kg/m³

Area = 550 m²

Height = 2.0 m

Depth = 0.55 m

Suppose we need to write an equation for the buoyant force on the empty barge in terms of the known data and find the value of force

We need to write the buoyant force equation

[tex]F_{b}=\rho\times V\times g[/tex]

The volume is

[tex]V=A\times h_{0}[/tex]

Put the value of volume into the buoyant force

[tex]F_{b}=\rho\times A\times h_{0}\times g[/tex]

We need to calculate the buoyant force

Put the value into the formula

[tex]F_{b}=1000\times550\times0.55\times9.8[/tex]

[tex]F_{b}=2964500\ N[/tex]

Hence, The buoyant force is 2964500 N.