A certain spinner is divided into 6 sectors of equal size, and the spinner is equally likely to land in any sector. Four of the 6 sectors are shaded, and the remaining sectors are not shaded. What is the probability that one spin of the spinner will land in a shaded sector?

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Answer:

2/3

Step-by-step explanation:

A certain spinner is divided into 6 sectors of equal size, and the spinner is equally likely to land in any sector. Four of the 6 sectors are shaded, and the remaining sectors are not shaded.

Probability is the likelihood that an event will occur. Probability is a selection over the number of observation.

There are 4 shaded portion of the spinner and two unshaded portion.

The probability that when the spinner is spinned the portion will liand on four is simply

4/6, divided to its lowest term.

2/3

The probability that when the spinner is spined the portion will land on four is simply [tex]\frac{2}{3}[/tex].

Given information:

A certain spinner is divided into [tex]6[/tex] sectors of equal size, and the spinner is equally likely to land in any sector. Four of the [tex]6[/tex] sectors are shaded, and the remaining sectors are not shaded.

According to question,

[tex]P(E)=\frac{\rm{No\;of\;favourable\;outcomes}}{\rm{Total\;no\;of\;outcomes}}[/tex]

Four of the [tex]6[/tex] sectors are shaded, and the remaining sectors are not shaded.

There are [tex]4[/tex] shaded portion of the spinner and two unshaded portions.

[tex]P(E)=\frac{4}{6}=\frac{2}{3}[/tex]

Hence, The probability that when the spinner is spined the portion will land on four is simply [tex]\frac{2}{3}[/tex].

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