contestada

An object at 27°C has its temperature increased to 37°C.

The power then radiated by this object increases by how many percent?
a. 3.3
b. 14
c. 37
d. 253

Respuesta :

Answer:

b. 14

Explanation:

[tex]T_{i}[/tex] = Initial temperature = 27 °C = 27 + 273 = 300 K

[tex]T_{f}[/tex] = Final temperature = 37 °C = 37 + 273 = 310 K

[tex]P_{i}[/tex] = Initial Power radiated by the object

[tex]P_{f}[/tex] = Final Power radiated by the object

We know that the power radiated is directly proportional to fourth power of the temperature. hence

[tex]\frac{P_{f}}{P_{i}} = \frac{T_{f}^{4} }{T_{i}^{4} }\\\frac{P_{f}}{P_{i}} = \frac{(310)^{4} }{(300)^{4} }\\\frac{P_{f}}{P_{i}} = 1.14\\P_{f} = (1.14) P_{i}[/tex]

Percentage increase in power is given as

[tex]\frac{(P_{f} - P_{i})\times100}{P_{i}} \\\frac{((1.14) P_{i} - P_{i})\times100}{P_{i}} \\14[/tex]