Answer:
Perimeter of triangle is 18.
Step-by-step explanation:
Given:
segment PQ = 1.8
segment PR = 8.2
∠PQR =90°
Since triangle is a right angle triangle with right angle at ∠Q.
Now by using Pythagoras theorem we get;
The square of one side is equal to sum of the square of other two side.
[tex]PQ^2+QR^2 = PR^2[/tex]
Substituting the given value we get;
[tex](1.8)^2+QR^2 = (8.2)^2\\\\3.24+QR^2 = 67.24\\\\QR^2 = 67.24-3.24\\\\QR^2= 64[/tex]
Now taking square root on both side we get;
[tex]\sqrt{QR^2} =\sqrt{64} \\\\QR = 8[/tex]
Now we need to find the perimeter of the triangle.
Perimeter of triangle is sum of all three side.
Framing in equation form we get;
Perimeter of triangle = PQ + QR +PR = 1.8 + 8 + 8.2 = 18
Hence Perimeter of triangle is 18.
