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A 20600 kg sailboat experiences an eastward force 17700 N due to the tide pushing its hullwhile the wind pushes the sails with a force of 60000 N directed toward the northwest (45◦ westward of North or 45◦ northward of West). What is the magnitude of the resultant acceleration of the sailboat?

Respuesta :

Answer:

2.23 m/s²

Explanation:

mass of sail boat, m = 20600 kg

Force along east, F1 = 17700 N

Force along north west, F2 = 60000 N

write the forces in vector form

[tex]\overrightarrow{F_{1}}=17700 \widehat{i}[/tex]

[tex]\overrightarrow{F_{2}}=60000\left ( - Cos45 \widehat{i}+Sin45\widehat{j}\right )[/tex]

[tex]\overrightarrow{F_{2}}=-42426.41\widehat{i}+42426.41\widehat{j}[/tex]

Net force acting on the boat

[tex]\overrightarrow{F}=\overrightarrow{F_{1}}+\overrightarrow{F_{2}}[/tex]

[tex]\overrightarrow{F}=17573.6\widehat{i}+42426.41\widehat{j}[/tex]

The magnitude of net force is given by

[tex]F=\sqrt{17573.6^{2}+42426.41^{2}}[/tex]

F = 45922 N

Acceleration = force / mass

a = 45922 / 20600

a = 2.23 m/s²

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