Answer:
Velocity at the bottom will be 16.66 m/sec
Explanation:
We have given mass of the object m = 5.5 kg
Angle which is made by the plane [tex]\Theta =30^{\circ}[/tex]
Distance traveled s = 72 m
Acceleration will be equal to [tex]a=g(sin\Theta -\mu cos\Theta )=9.8\times (sin30^{\circ}-0.35cos30^{\circ})=1.929m/sec^2[/tex]
Initial velocity u = 0 m /sec
We have to find the velocity at the bottom of the plane, that is final velocity v
From third equation of motion we know that
[tex]v^2=u^2+2as[/tex]
So [tex]v^2=0^2+2\times 1.929\times 72=277.77[/tex]
v = 16.66 m/sec
