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Two Ethernet cables of the same length are pulled taut at the same tension. Cable 2 hasfour times the weight of cable 1. Waves travel along the length of the cable 1 at a speedof 8.0 m/s. What is the speed, in m/s, of waves on cable 2?

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boffeemadrid

Answer:

4 m/s

Explanation:

T = Tension

m = Mass of string

Velocity of wave in string is given by

For first cable

[tex]v_1=\sqrt{\dfrac{T}{m}}=8[/tex]

For second cable

[tex]v_2=\sqrt{\dfrac{T}{4m}}\\\Rightarrow v_2=\dfrac{1}{2}\sqrt{\dfrac{T}{m}}\\\Rightarrow v_2=\dfrac{1}{2}\times 8\\\Rightarrow v_2=4\ m/s[/tex]

The speed of wave in cable two is 4 m/s

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