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A student pushes a 10 kg box with a force of 30 N at an angle 45 degrees below the horizontal . The box experi 21.2 N of force against the motion. What is the acceleration of the box?

Respuesta :

Answer:

Acceleration =0

Explanation:

There are two forces on the box in horizontal direction.

First one is horizontal component of 30N at 45°.

[tex]F=\frac{1}{\sqrt{2} }*30=21.2[/tex]

Another one is given in opposite to direction of motion mean opposite to this force.

Which is = 2.22 N

Now we know F (net) =mass*acceleration(center of mass)

21.2-21.2 =10*acceleration

acceleration =0

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