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These are the first six terms of a sequence with a1= - 3: - 3, 8, 19, 30, 41, 52, … Find a recursive formula for this sequence that is valid for n>1. Write your answer in simplest form.

Respuesta :

sam4040

Answer:

[tex]a(n+1)=a(n)+11[/tex]

Step-by-step explanation:

The difference between two consecutive elements is 11.

[tex]8=-3+11\\19=8+11\\30=19+11\\41=30+11\\52=41+11\\[/tex]

Hence [tex]a(n+1)=a(n)+11[/tex]

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