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What maximum force do you need to exert on a relaxed spring with a 1.2×104-n/m spring constant to stretch it 6.0 cm from its equilibrium position?

Respuesta :

Answer:

Maximum force will be equal to 720 N

Explanation:

We have given that spring constant [tex]k=1.2\times 10^4N/m[/tex]

Maximum stretch of the spring x = 6 cm = 0.06 m

We have to find the maximum force on the spring

We know that spring force is given by

[tex]F=kx=1.2\times 10^4\times 0.06=720N[/tex]

So the maximum force which is necessary to relaxed the spring will be eqaul to 720 N

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