Answer:
Hydraulic gradient=0.0173
Explanation:
The hydraulic head at the points A, B and C will be as follows
A=95-5=90 m
B=110-30=80 m
C=135-35= 100 m
By drawing the equipotential lines, the direction of ground water can be seen as in the triangle
The length of flow will be
[tex]L=\sqrt {1000^{2}-500^{2}}\approx 866.025 m[/tex]
The hydraulic gradient will be given by
[tex]i=\frac {\triangle h}{L}=\frac {95-80}{866.025}\approx 0.0173[/tex]