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A Ferris wheel, rotating initially at an angular speed of 0.500 rad/s, accelerates over a 7.00-s interval at a rate of 0.040 0 rad/s2 . What angular displacement does the Ferris wheel undergo in this 7-s interval? a. 4.48 rad b. 2.50 rad c. 3.00 rad d. 0.500 rad

Respuesta :

Answer:

Angular displacement will be 4.48 rad

So option (a) will be correct option

Explanation:

We have given initial angular acceleration [tex]\omega _i=0.5rad/sec[/tex]

Angular acceleration [tex]\alpha =0.04rad/sec^2[/tex]

Time t = 7 sec

We have to find the angular displacement

We know that angular displacement is given by

[tex]\Theta =\omega _it+\frac{1}{2}\alpha t^2=0.5\times 7+\frac{1}{2}\times 0.04\times 7^2=4.48rad[/tex]

So option (a) will be correct option

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