Answer:
Minimum power of compressor = 9.71 kW
Explanation:
The values of entropy, initial specific volume and enthalpy are obtained from the table for R-134a.
Entropy, s = 0.942 kJ/kg/K
Specific volume, [tex]v_{1}[/tex] = 0.12355
Enthalpy, [tex]h_{1}[/tex] = 241.4 kJ/kg
Final enthalpy can be found out from the table using the given pressure and entropy.
[tex]h_{2}[/tex] = 277.12 kJ/kg/K
Minimum power = [tex]\frac{dm}{dt} (h_{2} - h_{1})[/tex]
              = [tex]\frac{\frac{dV}{dt} }{v_{1} }[/tex]([tex]h_{2}-h_{1}[/tex])
Minimum power = 9.71 kW
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