Answer:
Please find the detailed answer as follows:
Explanation:
A. Step 1. The differential equation is
dB / dt = 0.015B - 5000
Step 2. now we must integrate it to find it ias a function of time
dB /0.015B - 500 = dt
Step 3. integrate
=> ln ( 0.015 B - 5000) = 0.015t + 0.015c
=> 0.015B - 5000 = e^0.015t .e^0.015c
here .e^0.015c is constant let it be Bo
b. =>B = 1/0.015 [ Bo e^0.015t + 5000 ]
at t = 0 , B = 5000
=> 5000 x 0.015 = Bo => B o = 75
c . B = 1/0.015 [ 75 e^0.015t + 5000 ]
put t = 10
=> B = $ 339142.50
