Respuesta :
The price of one vegetarian special lunch is $7 and price of one chicken special lunch is $8.
Step-by-step explanation:
Let,
Price of one vegetarian special lunch = x
Price of one chicken special lunch = y
According to given statement;
21x+40y=467 Â Â Â Eqn 1
28x+36y=484 Â Â Eqn 2
Multiplying Eqn 1 by 28
[tex]28(21x+40y=467)\\588x+1120y=13076\ \ \ Eqn\ 3[/tex]
Multiplying Eqn 2 by 21
[tex]21(28x+36y=484)\\588x+756y=10164\ \ \ Eqn\ 4[/tex]
Subtracting Eqn 4 from Eqn 3
[tex](588x+1120y)-(588x+756y)=13076-10164\\588x+1120y-588x-756y=2912\\364y=2912[/tex]
Dividing both sides by 364
[tex]\frac{364y}{364}=\frac{2912}{364}\\y=8[/tex]
Putting y=8 in Eqn 1
[tex]21x+40(8)=467\\21x+320=467\\21x=467-320\\21x=147[/tex]
Dividing both sides by 21
[tex]\frac{21x}{21}=\frac{147}{21}\\x=7[/tex]
The price of one vegetarian special lunch is $7 and price of one chicken special lunch is $8.
Keywords: linear equation, elimination method
Learn more about elimination method at:
- brainly.com/question/10081622
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The price of chicken specials is $8.
The price of  vegetarian specials is $7.
What are the system of equations that represent the question?
21v + 40s = 467 equation 1
28v + 36s = 484 Â equation 2
Where:
v = vegetarian specials
c= Â chicken specials
What is the price of chicken specials?
Multiply equation 1 by 28 and equation 2 by 21
588v + 1120s = 13076 equation 3
588 + 756s =10,164 equation 4
Subtract equation 3 from equation 4
364s = 2912
s = $8
What is the price of vegetarian specials?
Substitute for s in equation 1
21v + 40(8) = 467
21v = 467 - 320
21v = 147
v = $7
To learn more about simultaneous equations, please check: https://brainly.com/question/25875552
