Respuesta :
Answer:
v = 2.33 10⁷ mi / h
Explanation:
For this exercise we must observe that the velocity module is constant, so we can use the kinematic relation
v = d / t
The distance traveled in each orbit is the length of the circle
L = 2π r
The time it takes in orbit is called period (T)
Let's reduce the quantities
r = 8.9 10⁷ mi
t = 24 h (3600s / 1 h) = 86400 s
We replace
v = 2π r / T
Let's calculate
v = 2π 8.9 10⁷/86400
v = 6.47 10³ mi / s
v = 6.47 10³ mi / s (3600 s / 1h)
v = 2.33 10⁷ mi / h
Answer:
linear speed v = 23303166.67 mi/h
Explanation:
From linear speed v = angular speed w * radius r
And we have angular speed w = 2*pi/T
where T is the period
hence, v = 2*pi*r/T
Given:
r= 89,000,000 mi, T = 24 hours
Hence v = 2*3.142*89000000/24
linear speed v = 23303166.67 mi/h
