Answer:
C) three eudicots and one monocot.
Explanation:
Flowering plants are generally divided into two based on the number of seed leaves. These are:
- Monocots: these are flowering plants with only one seed leaf. Their leaves are usually long and narrow with parallel veination. Seed germination mode is hypogeal. Their stems are usually flesh and without branches and their roots are usually fibrous. Monocots' flowers are usually trimerous, that is, the flower parts are usually in threes.
- Eudicots: as opposed to monocots, they are flowering plants with two seed leaves. The mode of seed germination is epigeal, leaves are usually broad with net veination pattern and they posses tap root system. Flower parts are usually in fours of fives and their stems are usually wide with branches.
Let us look at which of the 2 groups the bunch of flowers collected by the florist belong:
Lilies have parallel vein - monocot
Wild carrot has large taproot - eudicot
Buttercups has five petals - eudicot
Daisies with two cotyledons - eudicot.
Hence, the bunch of flowers contain three eudicots and one monocot.
The correct option is C.
