Answer:
1 and 6.
Explanation:
The enthalpy of reaction (ΔH°rxn) can be calculated by the enthalpy of the formation (H°f) of the components:
ΔH°rxn = ∑n*H°fproducts - ∑n*H°freactants, where n is the number of the moles of the stoichiometric reaction.
So, if ∑n*H°freactants = 0, ΔH°rxn = ∑n*H°fproducts = ΔH°f of the products.
H°f = 0 if the compound is formed by only one element and it is in the ambiental conditions phase. In this case:
H°f of C(s, graphite) = 0
H°f of O₂(g) = 0
H°f of Na(s) = 0
H°f of Cl₂(g) = 0
Thus, it happens only for reactions 1 and 6.