Answer:
g =[tex] 0.1m/s^2 [/tex]
Explanation:
From the law of atmosphere
[tex] Nv(y) = n0*e^(-mgy/Kb*T) [/tex]
Given:
Kb = Boltzmann's constant = [tex] 1.38*10^-23 J/K [/tex]
temperature T = 20K
Mass M = 10^-19 kg
Since it is 30% of value above surface, therefore Nv = 0.3n0
Rearranging equation (I) to make g subject of the formula,
g = [ (Kb*T)*in(0.3n0 / n0) ] / (m*y)
Substituting each of the values given in the equation, we obtain
g =[tex] 0.1m/s^2 [/tex]