Answer:
slope of EF=[tex]\frac{5}{3}[/tex]
∠QSR=45°,
∠PTQ=90°
if RT=24
then SQ=48
square is always a rectangle
∠SUT=21°
Step-by-step explanation:
two line are perpendicular to each other if product of their slope equal to -1
[tex]m_{1}\times m_{2}[/tex]=-1
slope of HE=[tex]m_1[/tex]=-[tex]\frac{3}{5}[/tex]
slope of EF=[tex]m_2[/tex]
slope of EF=-1[tex]\frac{-5}{3}[/tex]=[tex]\frac{5}{3}[/tex]
slope of EF=[tex]\frac{5}{3}[/tex] answer
∠QSR=45°,
∠PTQ=90°
if RT=24
then SQ=48
square is always a rectangle
given ∠SUT=3x+6
∠RUS=5x-4
∠SUT=∠RUS
3x+6=5x-4
x=5
∠SUT=3x+6=15+6=21°
∠SUT=21°
