Answer:[tex]\frac{g}{4}[/tex]
Explanation:
Let m be the mass of Astronaut
M=mass of earth
G=Gravitational constant
R=radius of Earth
Force Exerted by Earth on Astronaut
[tex]F=\frac{GmM}{R^2}[/tex]
acceleration due to gravity is [tex]=\frac{F}{m}=g[/tex]
[tex]g=\frac{GM}{R^2}[/tex]
When it is at [tex]r=2R[/tex]
[tex]g'=\frac{GM}{(2R)^2}[/tex]
[tex]g'=\frac{GM}{4R^2}=\frac{g}{4}[/tex]
