Answer:
W = 0.1667 (G mM / Re)
Explanation:
The work is defined as
   dW = F .ds
where F is the force and ds of the displacement difference, the point represents the scalar product
In this case the force is radial from the satellite to the center of the plant and the direction coincides with the direction of the radius of the spherical earth, so it is work remains
    dW = - F dr
The force is the gravitational force is
    ∫ dw = G m M  ∫ dr / r²
   W = G m M (-1 / r)
Let's evaluate at r = 2Re and r = 3Re
  W = - GmM (1 / 3Re - 1 / 2Re)
  W = - GmM / Re (1/3 - ½)
  W = G m M / Re (-0.16667)
  W = 0.1667 (G mM / Re)
.
