Answer:
[tex]a=38.5 ft/sec^{2}[/tex]
Explanation:
Note that acceleration is the rate change of velocity i.e
[tex]acceleration=\frac{change in velocity}{change in time}\\a=\frac{dv}{dt} \\[/tex].
Since the velocity is giving as a variable dependent on the pressure, we have to differentiate implicitly both side with respect to time,i.e
[tex]\frac{dv}{dt}=1306*(1/2)p^{-1/2}\frac{dp}{dt} \\[/tex]
if we substitute value for the pressure as giving in the question and also since the rate change of pressure is 0.354psi/sec, we have
[tex]a=653*0.1667*0.354\\[/tex]
[tex]a=\frac{dv}{dt}=653(36)^{-1/2}*0.354\\ a=38.5 ft/sec^{2}[/tex]
