An electron that has an energy of approximately 6 eV moves between rigid walls with 1.00 nm of separation. Find: a. the quantum number n for the state of energy that the electron occupies. b. the precise energy of the electron.

Respuesta :

Answer:

a) n = 8 10⁴  , b)  The energy of the electron is 9.6 10⁻¹⁹ J

Explanation:

The movement of the electron will approximate the movement within a potential pit with infinite walls, in this case the energy is given by

         [tex]E_{n}[/tex] = (h² / 8mL) n²

Where n is an integer (n = 1, 2, 3 ...)

Let's reduce the distance to the SI system

        L = 1 nm = 1 10⁻⁹ m

        E = 6 eV (1.6 10⁻¹⁹J / 1 eV) = 9.6 10⁻¹⁹ J

Let's clear the equation

       n = √ [(8m L / h²) E]

Let's calculate

     n = √ [8  9.1 10⁻³¹  1 10⁺⁹ /(6.63 10⁻³⁴)²   9.6 10⁻¹⁹]

     n = √ (60,126 10⁸)

     n = 7.8 10⁴

     n = 8 10⁴

The energy of the electron is 9.6 10⁻¹⁹ J