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A student has two unopened 33 CL cans containing carbonated water. Can A has been stored in the garage 32 degrees and can B has been stored in the fridge 8 degrees. The student opens one can at the time, both cans make a fizz.

A. Can A will make a louder and stronger fizz than can B.
B. Can B will make a louder and stronger fizz than can A
C. The fizz will be the same for both cans
D. There is not enough information to predict which can will make the louder fizz

Respuesta :

znk

Answer:

A. Can A will make a louder and stronger fizz than can B.  

Explanation:

The solubility of a gas in a liquid decreases as the temperature increases, so the warmer can will have more undissolved carbon dioxide.

The warmer can will be under greater pressure, so it will make a louder and stronger fizz.

mickymike92

Since Can A is stored at higher temperature, it will have the higher gas pressure due to less solubility of the gas. Therefore, Can A will have a louder and stronger fizz than Can B, option A.

What is the relationship between solubility of a gas, its temperature and pressure at constant volume?

The solubility of a gas decreases with increase in temperature.

The pressure of a gas however, increases with increase in temperature.

How would temperature and pressure affect the strength of fizz made by the carbonated water?

The fizz of the can of carbonated water will depend on the pressure of the gas within.

Since Can A is stored at higher temperature, it will have the higher gas pressure.

Therefore, Can A will have a louder and stronger fizz than Can B, option A.

Learn more about about solubility, temperature and pressure of gases at: https://brainly.com/question/17071337

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