Answer:
Mass of the disk will be 2.976 kg
Explanation:
We have given force F = 45 N
Radius of the disk r = 0.12 m
Angular acceleration [tex]\alpha =140rad/sec^2[/tex]
We know that torque [tex]\tau =I\alpha[/tex]
And [tex]\tau =Fr[/tex]
So [tex]Fr=I\alpha[/tex] , here I is moment of inertia
So [tex]50\times 0.12=I\times 140[/tex]
[tex]I=0.0428kgm^2[/tex]
We know that moment of inertia [tex]I=\frac{1}{2}mr^2[/tex]
So [tex]0.0428=\frac{1}{2}\times m\times 0.12^2[/tex]
m = 2.976 kg
