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A golfer takes two putts to get his ball into the hole once he is on the green. The first putt displaces the ball 8.4 m east, and the second 4.33 m south. What displacement would have been needed to get the ball into the hole on the first putt?

Respuesta :

Khoso123

Answer:

d=9.45 m

And directed

Ī±=62.7ā°

Explanation:

The Pythagoras Theorem

"The theorem, also known as the Pythagorean theorem, states that the square of the length of the hypotenuse is equal to the sum of squares of the lengths of other two sides of the right-angled triangle"

so for this problem

[tex]d^{2}=b^{2}+c^{2}\\ Ā  d=\sqrt{b^{2}+c^{2}}\\ d=\sqrt{(8.4)^{2}+(4.33)^{2} Ā }\\ d=9.45m[/tex]

And directed

Ī±=tanā»(8.4/4.33)

Ī±=62.7ā°

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