Which of the following samples will have the greatest volume at STP?a. 22 g Neb. 22 g Hec. 22 g O2d. 22 g Cl2e. All of these samples would have the same volume at STP.

Respuesta :

Answer:

He

Explanation:

According to Avogadro's law, at constant pressure and temperature, the volume of the gas is directly proportional to the moles of the gas.

Thus,

Moles of [tex]Ne[/tex]:-

Mass of the gas = 22 g

Molar mass of Ne = 20.1797 g/mol

The formula for the calculation of moles is shown below:

[tex]moles = \frac{Mass\ taken}{Molar\ mass}[/tex]

Thus,

[tex]Moles= \frac{22\ g}{20.1797\ g/mol}[/tex]

[tex]Moles_{Ne}= 1.0902\ mol[/tex]

Moles of [tex]He[/tex]:-

Mass of the gas = 22 g

Molar mass of He = 4.002602 g/mol

[tex]Moles= \frac{22\ g}{4.002602\ g/mol}[/tex]

[tex]Moles_{He}= 5.49642\ mol[/tex]

Moles of [tex]O_2[/tex]:-

Mass of the gas = 22 g

Molar mass of [tex]O_2[/tex] = 31.998 g/mol

[tex]Moles= \frac{22\ g}{31.998\ g/mol}[/tex]

[tex]Moles_{O_2}= 0.68754\ mol[/tex]

Moles of [tex]Cl_2[/tex]:-

Mass of the gas = 22 g

Molar mass of [tex]Cl_2[/tex] = 70.906 g/mol

[tex]Moles= \frac{22\ g}{70.906\ g/mol}[/tex]

[tex]Moles_{Cl_2}= 0.31026\ mol[/tex]

Thus, more the number of moles, more the volume. Thus, He will have the greatest volume at STP.