The local animal shelter throws a dog-themed party. Humans, h, and dogs, d are both invited. The event space imposes two restrictions on the party: there can only be 120 dogs and humans combined, and, to keep things manageable, there must be 1 human to every 3 dogs.
This situation can be represented by a system of two linear equations. One of these equations is given. Write the second equation in the box.




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Answer:

The system of equations can be expressed like

[tex]\left\{\begin{matrix}h+d=120\\ 3h-d=0\end{matrix}\right.[/tex]

Step-by-step explanation:

System of Two Linear Equations

It refers to situations where conditions are given in the form

[tex]\left\{\begin{matrix}ax+by=c\\ dx+ey=f\end{matrix}\right.[/tex]

Where x and y are the unknown variables and a,b,c,d,e,f are known constants

The problem describes a situation where one event space imposes two restrictions on a dog-themed party. The first one is there can only be 120 dogs and humans combined. Being h the number of humans, and d the number of dogs, then

[tex]h+d=120[/tex]

The other condition is there must be 1 human to every 3 dogs, we can model it by

[tex]d=3h[/tex]

Rearranging:

[tex]3h-d=0[/tex]

The system of equations can be expressed like

[tex]\left\{\begin{matrix}h+d=120\\ 3h-d=0\end{matrix}\right.[/tex]

Note: The solution of the system is h=30 humans and d=90 dogs