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A 0.3 kg rubber ball is dropped from the window of a building. It strikes the sidewalk below at 30 m/s and rebounds up at 20 m/s. The magnitude of the impulse due to the collision with the sidewalk is:______.

Respuesta :

Answer:

I = 15 kg.m/s

Explanation:

given,

mass of ball = 0.3 Kg

speed of the ball = 30 m/s

rebound speed = 20 m/s

impulse = ?

impulse is equal to change in momentum

I = m (Δ v)

I = m (v₂ - v₁)

I = 0.3 x (20 - (-30))

I = 0.3 x (50)

I = 15 kg.m/s

Impulse due to collision with the side walk is equal to I = 15 kg.m/s

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