Answer:
the magnitude of the total angular momentum of the blades is 743.71 kg·m²
Explanation:
Converting the angular speed into radians per second:
ω = 334 rpm · (2π rad / 1 rev) · (1 min / 60 s)
ω = 34.98 rad/s
The rotational kinetic energy of the blades is given by:
EK = 1/2 I ω²
where
Therefore, rearranging the above equation, we get:
1/2 I ω² = EK
I ω² = 2 EK
I = 2(EK) / ω²
I = 2(4.55 × 10⁵ J) / (34.98 rad/s)²
I = 743.71 kg·m²
Therefore, the magnitude of the total angular momentum of the blades is 743.71 kg·m².
