Answer:
Rms speed of the particle will be [tex]38.68\times 10^8m/sec[/tex]
Explanation:
We have given mass of the air particle [tex]m=5\times 10^{-16}kg[/tex]
Gas constant R = 8.314 J/mol-K
Temperature is given T = [tex]27^{\circ}C=273+27=300K[/tex]
We have to find the root mean square speed of the particle
Which is given by [tex]v_{rms}=\sqrt{\frac{3RT}{m}}=\sqrt{\frac{3\times 8.314\times 300}{5\times 10^{-16}}}=38.68\times 10^8m/sec[/tex]
So rms speed of the particle will be [tex]38.68\times 10^8m/sec[/tex]
