Answer:
X must be between 1818 and 5454
Step-by-step explanation:
The average A is the sum of the four notes divided by 4. We call X the value of the yet unknown fourth note, then
[tex] A = \frac{9393+8282+8787+X}{4} [/tex]
If you want A to be between 7070 and 7979, then we need X such that
[tex] [tex]7070 \leq \frac{9393+8282+8787+X}{4} \leq 7979 \, \rightarrow 28280 \leq 9393+8282+8787+X< 31916 \\\rightarrow 28280-9393-8282-8787 \leq X \leq 31916 - 9393-8282-8787 \, \rightarrow 1818 \leq X \leq 5454[/tex]
Therefore, X must be between 1818 and 5454.