Answer:
276.48 atm → CH₄
27.3 atm → C₂H₆
3.38 atm → C₃H₈
Explanation:
Percentages of each gas, are the mole fraction
0.9 CH₄
0.089 C₂H₆
0.011 C₃H₈
Mole fraction = Partial pressure each gas/ Total pressure
0.9 = Partial pressure CH₄ / 307.2 kPa
307.2 kPa . 0.9 = 276.48 atm
0.089 = Partial pressure C₂H₆ / 307.2 kPa
307.2 kPa . 0.089 = 27.3 atm
0.011 = Partial pressure C₃H₈ / 307.2 kPa
307.2 kPa . 0.011 = 3.38 atm
The partial pressure of each component of the gas are:
1. The partial pressure of CH₄ is 276.48 KPa
2. The partial pressure of C₂H₆ is 27.34 KPa
3. The partial pressure of C₃H₈ is 3.38 KPa
We'll begin by calculating the mole fraction of each gas.
Percentage of CH₄ = 90%
Total = 100%
Mole fraction = mole / total
Mole fraction CH₄ = 90 / 100
Percentage of C₂H₆ = 8.9%
Total = 100%
Mole fraction = mole / total
Mole fraction C₂H₆ = 8.9 / 100
Percentage of C₃H₈ = 1.1%
Total = 100%
Mole fraction = mole / total
Mole fraction C₃H₈ = 1.1 / 100
Finally, we shall determine the partial pressure of each gas. This can be obtained as follow:
1. Determination of the partial pressure of CH₄
Mole fraction CH₄ = 0.9
Total pressure = 307.2 KPa
Partial pressure = mole fraction × Total pressure
Partial pressure of CH₄ = 0.9 × 307.2
Partial pressure of CH₄ = 276.48 KPa
2. Determination of the partial pressure of C₂H₆
Mole fraction C₂H₆ = 0.089
Total pressure = 307.2 KPa
Partial pressure = mole fraction × Total pressure
Partial pressure of C₂H₆ = 0.089 × 307.2
Partial pressure of C₂H₆ = 27.34 KPa
3. Determination of the partial pressure of C₃H₈
Mole fraction C₃H₈ = 0.011
Total pressure = 307.2 KPa
Partial pressure = mole fraction × Total pressure
Partial pressure of C₃H₈ = 0.011 × 307.2
Partial pressure of C₃H₈ = 3.38 KPa
Learn more: https://brainly.com/question/15754440
