Answer:
Acceleration = 2.35 m/[tex]s^{2}[/tex]
Speed = 8.67 m/s
Explanation:
The coefficient of friction , u =0.3
The angle of incline = 30°
The two forces acting on block are weight and friction.
weight along the incline = mg cos60° = [tex]\frac{mg}{2}[/tex] = 0.5 mg
Friction along incline = umg cos30° = mg [tex]0.3\times \frac{\sqrt{3}}{2}[/tex]
Friction along incline = 0.26 mg
Net force acting on the weight = (0.5 - 0.26) mg = 0.24 mg
Acceleration = [tex]\frac{net force}{mass}[/tex] = 0.24 g = 2.35 m/[tex]s^{2}[/tex]
The height of incline = 8 m
Length of the inclined edge = 16 m
[tex]v^{2}=u^{2}+2as[/tex]
[tex]v^{2}= 2\times 0.24 \times 9.8\times 16[/tex]
v= 8.67 m/s
