Determine what shape is formed for the given coordinates for ABCD, and then find the perimeter and area as an exact value and rounded to the nearest tenth. A (−10, 5), B (−7, 1), C (1, 7), D (−6, 8)

Respuesta :

Answer:

Perimeter = 27 units

Area = 37.5 sq. units

Step-by-step explanation:

We have to find the length of all the sides to determine what kind of quadrilateral this is.

Length of AB = [tex]\sqrt{(-10+7)^{2}+(5-1)^{2}} = \sqrt{9+16} =\sqrt{25}= 5[/tex]

Length of BC = [tex]\sqrt{8^{2}+6^{2}} = 10[/tex]

Length of CD = [tex]\sqrt{7^{2}+1^{2}}[/tex] = 5[tex]\sqrt{2}[/tex]

Length of DA =[tex]\sqrt{4^{2}+3^{2}}[/tex]= 5

The shape is a quadrilateral.

To find the perimeter sum the length of all the sides,

PERIMETER = 5+10+5[tex]\sqrt{2}[/tex]+5 =27 units

We can find area by finding areas of triangles separately.

Area of ΔABC = 25 sq. units

Area of ΔACD = 12.5 sq. units

Area of quadrilateral= 25 + 12.5 = 37.5 sq. units