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A -kilogram car travels at a constant speed of 20. meters per second around a horizontal circular track. The diameter of the track is meters. The magnitude of the car's centripetal acceleration is:_______

Respuesta :

Answer:

The centripetal acceleration of the car is [tex]8\ m/s^2[/tex].

Explanation:

Let the mass of the car, [tex]m=10^3\ kg[/tex]

Diameter of the circular path, d = 100 m

Speed of car, v = 20 m/s

Radius, r = 50 m

When an object moves in a circular path, the centripetal acceleration acts on it. It is given by :

[tex]a=\dfrac{v^2}{r}[/tex]

[tex]a=\dfrac{(20\ m/s)^2}{50\ m}[/tex]

[tex]a=8\ m/s^2[/tex]

So, the centripetal acceleration of the car is [tex]8\ m/s^2[/tex]. Hence, this is the required solution.

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