Answer:
-1.00
Step-by-step explanation:
Given that a  publisher reports that 45% of their readers own a laptop. A marketing executive wants to test the claim that the percentage is actually different from the reported percentage.
Sample size n =190
Sample proportion p = 0.41
[tex]H_0: p = 0.45\\H_a: p \neq 0.45[/tex]
(Two tailed test )
Assuming H0 to be true
std error = [tex]\sqrt{pq/n} =\sqrt{0.45*0.55/155} \\=0.0400[/tex]
p difference = -0.04
Test statistic = p differencce/std error
= -1
Hence test statistic is -1.00
