Answer: The starting temperature when I left in °C is 26.70
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas = p
[tex]P_2[/tex] = final pressure of gas = [tex]\frac{p}{10}[/tex]
[tex]V_1[/tex] = initial volume of gas = v
[tex]V_2[/tex] = final volume of gas = [tex]5\times v[/tex]
[tex]T_1[/tex] = initial temperature of gas = ?
[tex]T_2[/tex] = final temperature of gas = [tex]-123.15^oC=273+(-123.15)=149.85K[/tex]
Now put all the given values in the above equation, we get:
[tex]\frac{p\times v}{T_1}=\frac{\frac{p}{10}\times 5\times v}{149.85K}[/tex]
[tex]T_1=299.70K=(273-299.70)^0C=-26.70^0C[/tex]
